got another problem
consider again the figure above
b' is known (V2
a-a' is know (V1
The trick is that a is not know, nor is a'! We only know the distance between them.
Find a and b
I'm not sure there is a single solution. I guess there will be a formula of b against a.
From the equation x2
I have (a-V1
if k = (a-V1
b = V2
/ sqrt( 1-k )
So here I have formula of b against a but when I draw it on screen it doesn't work.
The idea is knowing M point and its opposite N, draw an elliptic Arc through those 2 points and point a. but center of ellipse is not know.