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  setSchedulingBounds() question  (Read 1386 times)
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Offline Yoda

Junior Newbie





« Posted 2004-02-13 11:56:43 »

I'm starting a little project in Java3D and I'm trying to get a better understanding of how setSchedulingBounds() works.

To give a very simple example, consider the following lines from HelloJava3Dd.java:

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// a bounding sphere specifies a region a behavior is active
     // create a sphere centered at the origin with radius of 1
     BoundingSphere bounds = new BoundingSphere();
      rotator.setSchedulingBounds(bounds);
      objSpin.addChild(rotator);


No problem so far.  ColorCube rotates fine.

Now change:
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BoundingSphere bounds = new BoundingSphere();

to
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new BoundingSphere(new Point3d(0.0, 0.0, 0.0), 1.0);


Still OK, as I understand things, this is pretty much the same as the empty constructor.  ColorCube still rotates fine.

Now, if I comment out the following line, the ColorCube won't rotate.  Also as expected.
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rotator.setSchedulingBounds(bounds);


Here's my problem/question:
If I change the default position of the bounding sphere or give it a really small radius, the ColorCube still rotates fine.  Should the bounding sphere intersect the ColorCube at any (however small) position or at all positions?  I'm failing to see a tight correlation between the location/size of the bounding sphere and the rotation.

For a ColorCube constructed with a scale of 0.4, the rotation will work for the first bounding sphere below, but not for the second.

This works:
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BoundingSphere bounds = new BoundingSphere(new Point3d(30.0, 30.0, 30.0), 0.0001);


This doesn't:
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BoundingSphere bounds = new BoundingSphere(new Point3d(40.0, 40.0, 40.0), 0.0001);


Thanks for your help!
Offline Yoda

Junior Newbie





« Reply #1 - Posted 2004-02-13 20:10:09 »

Think I found my answer in Selman's book (pg. 165).  "When the Bounds for a Behavior and the ViewPlatform's activation radius intersect, the Behavior is scheduled for processing."

My understanding (now) is that the Bounds for a Behavior don't have to be anywhere near the actual object(s) that the Behavior is performed upon.  If I place a ColorCube out of site, but my rotator Behavior bounds intersect the ViewPlatform's activation radius, the ColorCube will spin out of sight.  Likewise, if I place my ColorCube in view, but add rotator Bounds outside of the ViewPlatform's activation radius, the ColorCube will be visible, but won't rotate.

Hopefully a moment of clarity.
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