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 [Scala] Finding the intersect of functions  (Read 1879 times) 0 Members and 1 Guest are viewing this topic.
saucymeatman
 « Posted 2014-04-07 02:29:20 »

Ok,before someone reminds me that this is JavaGaming.org and not ScalaGaming.org Scala still runs on the JAVA virtual machine, so take that!

Lets say we have two anonymous functions (or lambdas) :
 1  2 `val f1 = (x:Int) => x-1val f2 = (x:Int) => -x+1`

How do we find the value of x that will result in the same output?

So the method signature would look somthing like this :
 1  2 `type Function = Int => Intdef intercept(a:Function, b:Function):Int = ????????`
Riven
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Hand over your head.

 « Reply #1 - Posted 2014-04-07 05:34:53 »

This is math problem.

Each function results in a straight line. Just find the intersection-point, if any.

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Roquen

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 « Reply #2 - Posted 2014-04-07 08:42:35 »

{x->1}...can scala do exp rewritting?
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Danny02
 « Reply #3 - Posted 2014-04-07 08:50:09 »

Let's say that you don't know anything about these functions (linear, quadratic whatever). You can than do a numerical approximation, most of the time in an iterative fashion.
The most common method was invented by Newton.

So you would subtract one of the function from the over and then with the help of the above method approximated the intersection point.
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 « Reply #4 - Posted 2014-04-07 08:51:25 »

How do you automatically get the derivate? (Or can scala replace types so you can use dual numbers?)
Danny02
 « Reply #5 - Posted 2014-04-07 08:53:05 »

dunno, calculate the tangent yourself with a small sample size.

ps: you can probably write a solver macro to do all the hard work at compile time
Roquen

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 « Reply #6 - Posted 2014-04-07 08:54:37 »

The example isn't really clear...like is the field of integers only of interest?  Wait scratch that...what do you really want to do?
saucymeatman
 « Reply #7 - Posted 2014-04-07 10:56:40 »

Let's say that you don't know anything about these functions (linear, quadratic whatever).Newton.
This is what I meant sorry.
Ill look into this method.
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