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  Making random numbers within an array?  (Read 480 times)
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Offline wreed12345

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« Posted 2012-12-01 22:18:47 »

I am trying to use this code to define a new random to a member of an array but it is not working Sad any ideas?
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ballupdate(GameScreen.sballX[0]);

this is a much simplified version
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   public void ballupdate(int apple) {
      apple = random.nextInt(600) + 1;
   }

Offline sproingie

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« Reply #1 - Posted 2012-12-01 22:29:11 »

apple is a parameter, which is a local variable.  You're writing to it, doing nothing with it, and returning.  You need to return the value and assign it to the proper array position in the caller. 

This is fairly intro-level stuff -- have you gone through the java tutorial on oracle.com yet?
Offline wreed12345

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« Reply #2 - Posted 2012-12-01 22:32:48 »

how would i do that?

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Offline matheus23

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« Reply #3 - Posted 2012-12-01 22:34:15 »

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GameScreen.sballx[0] = random.nextInt(600) + 1;


or

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public int ballupdate() {
    return random.nextInt(600) + 1;
}
[...]
GameScreen.sballx[0] = ballupdate();


Both give exactly the same results.

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Offline marcuiulian13

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« Reply #4 - Posted 2012-12-01 22:41:52 »

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public void ballupdate() {
    return random.nextInt(600) + 1;
}
[...]
GameScreen.sballx[0] = ballupdate();


Void function returning an int?  Shocked

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Offline matheus23

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« Reply #5 - Posted 2012-12-01 22:46:58 »

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public void ballupdate() {
    return random.nextInt(600) + 1;
}
[...]
GameScreen.sballx[0] = ballupdate();


Void function returning an int?  Shocked

 Roll Eyes Edited, fixed Smiley

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