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  Distance formula in Java?  (Read 1657 times)
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Offline SkyAphid
« Posted 2012-06-03 23:45:36 »

I don't know if it has something to do with OpenGL or it's just Java in general but..

1  
distance = (int) Math.sqrt(((ent.getX() - x) ^ 2) + ((ent.getY() - y) ^ 2));


I sometimes get NaN from that.

Although, if I move it around like this..

1  
distance = (int) Math.sqrt(((x - ent.getX()) ^ 2) + ((y - ent.getY()) ^ 2));


Instances where it would NaN would return normal numbers, but on the otherhand the instances where it returns a normal number is now NaN.

What did I do wrong? Both X/Y's are on concurrent matrices, so what is it?


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Offline Riven
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« Reply #1 - Posted 2012-06-03 23:54:34 »

1  
value ^ 2
means XOR



you either need:
1  
return (int) Math.sqrt(Math.pow(x - ent.getX()), 2.0) + Math.pow(y - ent.getY(), 2.0));


or more readable and much faster:
1  
2  
3  
dx = x - ent.getX();
dy = y - ent.getY();
return (int)Math.sqrt(dx*dx + dy*dy);

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Offline SkyAphid
« Reply #2 - Posted 2012-06-04 00:20:55 »

Thanks!!

“Life is pretty simple: You do some stuff. Most fails. Some works. You do more of what works. If it works big, others quickly copy it. Then you do something else. The trick is the doing something else.” ~Leonardo da Vinci
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Offline ReBirth
« Reply #3 - Posted 2012-06-04 03:10:59 »

Also there's distance method on... Point/Point2D.

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