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  Boomerang Pathfinding  (Read 1027 times)
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Offline westloar

Junior Member





« Posted 2012-04-22 21:10:48 »

Hey all my new game features a boomerang and I have figured two ways to calculate the path for the boomerang (without the return arc, I'll work on that later).

First of all draw a line of "range" length from the centre of the hero sprite, divide that into 20 - "speed" nodes (i.e. higher speeds leads to less nodes leads to it moving along its path faster) and store the nodes in an array to be sequentially ran through by each call of updateSprite()

Second create a for loop that increments and X and Y position each iteration and stores the results as nodes in an array.

My question is, which is less memory/processor intensive?
Offline SkyAphid
« Reply #1 - Posted 2012-04-22 21:33:46 »

Hey all my new game features a boomerang and I have figured two ways to calculate the path for the boomerang (without the return arc, I'll work on that later).

First of all draw a line of "range" length from the centre of the hero sprite, divide that into 20 - "speed" nodes (i.e. higher speeds leads to less nodes leads to it moving along its path faster) and store the nodes in an array to be sequentially ran through by each call of updateSprite()

Second create a for loop that increments and X and Y position each iteration and stores the results as nodes in an array.

My question is, which is less memory/processor intensive?

Neither should really damage your memory too much...go with the one that'd be easier to program.

“Life is pretty simple: You do some stuff. Most fails. Some works. You do more of what works. If it works big, others quickly copy it. Then you do something else. The trick is the doing something else.” ~Leonardo da Vinci
Offline westloar

Junior Member





« Reply #2 - Posted 2012-04-23 00:19:54 »

I thought as much, I'm new to java and wondered more for my own knowledge, do you think creating the line would use more memory, just out of interest?
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Offline theagentd
« Reply #3 - Posted 2012-04-23 04:13:13 »

A line is just 2 points, so 8 - 16 bytes depending on what variable types you use. How many hundred million boomerangs do you need? If you only need like 200 000 you should be fine with lines.  Wink

Myomyomyo.
Offline westloar

Junior Member





« Reply #4 - Posted 2012-04-23 08:49:07 »

I think OCD is the key word here, but thanks Smiley
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