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  Calculating Distance Interval  (Read 1199 times)
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Offline ghostsoldier23

Junior Member


Medals: 1



« Posted 2012-03-11 20:33:46 »

Ok I'm totally confusing myself here and drawing a blank...

If I have change in x and change in y (dx and dy) over a specified amount of time in milliseconds, and I calculate time intervals by (time / dx) and (time / dy), how do
I calculate the distance intervals for each time period?

This is a stupid math question... but I'm seriously just blanking out here...
Offline _Al3x

Senior Member


Medals: 7


Indie Games FTW!


« Reply #1 - Posted 2012-03-12 00:55:52 »

How about using 2 more variables oldDxInterval and oldDyInterval? Then you do:

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oldDxInterval = interval;
interval = time /dx;
DxDistance = oldDxInterval - interval; //Or viceversa, don't know lol
interval = time / dy;
DyDistance = oldDyInterval - interval;


I hope it helps Smiley

Offline ra4king

JGO Kernel


Medals: 345
Projects: 2
Exp: 5 years


I'm the King!


« Reply #2 - Posted 2012-03-12 03:46:39 »

Uhhhh why would you divide time by the deltaX and deltaY? You want the other way around to get the distance for each time period:
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x += dx / time;
y += dy / time;

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Offline ghostsoldier23

Junior Member


Medals: 1



« Reply #3 - Posted 2012-03-20 23:36:00 »

Uhhhh why would you divide time by the deltaX and deltaY? You want the other way around to get the distance for each time period:
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x += dx / time;
y += dy / time;


Time intervals not distance intervals.

Should it just be:
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dintx = dx / time;
dinty = dy / time;
tintx = time /dx;
tinty = time /dy;
Offline ghostsoldier23

Junior Member


Medals: 1



« Reply #4 - Posted 2012-03-20 23:37:07 »

How about using 2 more variables oldDxInterval and oldDyInterval? Then you do:

1  
2  
3  
4  
5  
oldDxInterval = interval;
interval = time /dx;
DxDistance = oldDxInterval - interval; //Or viceversa, don't know lol
interval = time / dy;
DyDistance = oldDyInterval - interval;


I hope it helps Smiley

Wait... what does that do?  Could you clarify a bit Tongue ?
Offline jimeowan

Junior Member


Medals: 1
Projects: 1



« Reply #5 - Posted 2012-03-21 16:06:34 »

Ok I'm totally confusing myself here and drawing a blank...

If I have change in x and change in y (dx and dy) over a specified amount of time in milliseconds, and I calculate time intervals by (time / dx) and (time / dy), how do
I calculate the distance intervals for each time period?

This is a stupid math question... but I'm seriously just blanking out here...

I think what you're looking for is:

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distanceintervalx = dx * time period / time
distanceintervaly = dy * time period / time


Example:

dx = 5m, dy = 10m, dt = 2s
If you want a time period of 1s, then:

distanceintervalx = 5 * 1 / 2 = 2.5 m/s
distanceintervaly = 10 * 1 / 2 = 5 m/s


That's what we usually call speed  Grin

Author of "The Little Scientist" (judging panel winner for Java4K 2012 </brag>)
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