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  [SOLVED] How to search a text file?! Please help!  (Read 579 times)
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Offline HyperReal

Senior Newbie





« Posted 2011-11-17 21:46:46 »

I would like to search a simple text file: for instance let's see the following is the contents of my text file...

Edward Password123
Cedrick pASSWORD321

How do I parse this so that I give my scanner object a username and it finds the respective password?  Each username and password are on seperate lines all will be divided by a " " ( a space).  How do I go about doing such a thing?

Here's what I have so far...

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package test;

import java.io.*;
import java.util.*;

public class TestFileReader
{
    public void readFile(String fileName)
    {
        try
        {
            File file = new File(fileName);
            Scanner scan = new Scanner(file);
           
            while (scan.hasNextLine())
            {
                System.out.println(scan.nextLine());
            }
        } catch (FileNotFoundException e) { System.out.println("File not found."); }
    }

    public void writeToFile(String fileName, String Username, String Password)
    {
        try
        {
            FileWriter writer = new FileWriter(fileName, true);
            writer.write("\n" + Username + " " + Password);
            writer.flush();
        } catch (IOException e) {}
    }
   
    public void getPassword(String fileName, String Username)
    {
        try
        {
            File file = new File(fileName);
            Scanner scan = new Scanner(file);
           
        } catch (FileNotFoundException e) { System.out.println("File not found."); }
       
    }
}

Offline Gingerious

Junior Duke


Medals: 2



« Reply #1 - Posted 2011-11-17 22:04:15 »

If you're already reading the file line-by-line, you can use a string tokenizer to separate the username and password:

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 StringTokenizer st = new StringTokenizer("this is a test");
     while (st.hasMoreTokens()) {
         System.out.println(st.nextToken());
     }


Output:

this
is
a
test

Just replace "this is a test" with the nextline read and you can parse out the username and password to do individual checks on them.
Offline HyperReal

Senior Newbie





« Reply #2 - Posted 2011-11-17 22:08:44 »

Really what I want to do is to have something that when it's given a username it finds that username's password...
I don't really need to separate everything out like that.
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Offline HyperReal

Senior Newbie





« Reply #3 - Posted 2011-11-17 23:23:23 »

Ok... I figured it out..

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package test;

import java.io.*;
import java.util.*;

public class TestFileReader
{
    static String getPassword( String userName )
    {
        try
        {
            BufferedReader r = new BufferedReader( new FileReader("file"));
            String line = null;
           
            while ((line = r.readLine()) != null)
            {
                String[] pair = line.split(" +");
               
                if (pair[0].equalsIgnoreCase(userName))
                {
                    r.close();
                    return pair[1];
                }
            }
            return null;
        } catch (IOException e) { throw new RuntimeException( e ); }
    }
}
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