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  Decreasing the sensitivity  (Read 1637 times)
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Offline AppleWilliam

Senior Newbie





« Posted 2010-08-04 19:34:25 »

The xbox controller is extremlly sensitive.  I was wondering how I should go about decreasing the sensitivity.  I was thinking about dividing the poll data by 2.  Would that work or is there an easier way.
Offline Riven
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« Reply #1 - Posted 2010-08-04 19:37:50 »

maybe...

Math.sqrt(value)

or...

Math.pow(value, 1.0 / factor)

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Offline AppleWilliam

Senior Newbie





« Reply #2 - Posted 2010-08-04 19:50:47 »

maybe...

Math.sqrt(value)

or...

Math.pow(value, 1.0 / factor)
I tried that. something like this:
1  
2  
3  
4  
   public void theta1(double x, double y){
      y = Math.pow(y,1/2);
      x = Math.pow(x,1/2);
      setTheta(Math.atan2(y, x));

My Y and X are dependant on each other.  Since they are in a ratio, theta will always be the same if x and y are being modified by the same factor
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Offline Riven
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Exp: 16 years


Hand over your head.


« Reply #3 - Posted 2010-08-04 19:56:25 »

Obviously, you have to 'adjust' the vector length, not the input values.

Besides that: 1/2==0 so your code doesn't work.

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Offline Nate

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« Reply #4 - Posted 2010-08-05 05:35:25 »

Well, often lots of "practice" helps. Can't help you with the vector length though.

Offline Roquen
« Reply #5 - Posted 2010-08-05 06:22:49 »


If you mean 'noisy' then you could start with a low pass filter:

x = f(x0+x1)-x0

where 'x0' is the previous filtered sample, 'x1' is the new sample and 'f' is the weight of the filter, on (0,1).
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