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  Simple Array Question  (Read 1613 times)
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Offline Cero
« Posted 2009-12-15 15:25:51 »

Does

1  
int x;


use the same amount of memory, as

1  
int[1][1][1][1][1] x;


?

Offline pjt33
« Reply #1 - Posted 2009-12-15 15:43:39 »

No.
Online Riven
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Hand over your head.


« Reply #2 - Posted 2009-12-15 17:41:09 »

1  
int[1][1][1][1][1] x;


this is an object int[][][][][] pointing to the object int[][][][] pointing to the object int[][][] pointing to the object int[][] pointing to the object int[] pointing to a primitive int

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Offline Cero
« Reply #3 - Posted 2009-12-17 10:14:25 »

I have a class in which I have an
Object[][]

because there are cases in which both dimensions are used and some cases in which the second dimension is just 1
I thought this was a better solution than to kinda declare
Object a[]
and
Object b[][]
and do some ifs, because I hoped my solution would use less memory

and yea I should note that this is a performance critical class, so its should be done the best way.

Offline pjt33
« Reply #4 - Posted 2009-12-17 12:21:42 »

You could always flatten the array (assuming you know the dimensions at creation time).
Offline Cero
« Reply #5 - Posted 2009-12-17 17:18:51 »

how does that work exactly ?

Offline Eli Delventhal

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« Reply #6 - Posted 2009-12-17 19:07:12 »

how does that work exactly ?

1  
2  
3  
4  
5  
6  
7  
8  
9  
10  
11  
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Object[width][height]

becomes

Object[width*height]

where an access like:

Object[i][j]

becomes

Object[i*arrayWidth+j]

See my work:
OTC Software
Offline Cero
« Reply #7 - Posted 2009-12-17 23:21:11 »

ah, clever.

thanks

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