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  audioInputStream with Zip  (Read 1942 times)
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Offline mlefler

Innocent Bystander




Java games rock!


« Posted 2003-08-24 20:48:46 »

I'm currently trying to load a group of files from a single zip which inlcudes; images, text files, data files, wav files and anything else my little heart desires.  The problem is that all the files that I recieve from the zip as a byte array, work fine - except for the wav files.  If I load the wav file from a URL it works fine.  The clip that gets created by the byte array appears to be a valid format. Oh and before anybody suggest putting the files into my jar - that is not an option. Here is the code that I'm using.  And thanks for taking a look:


     public void createClip( URL data ) //works
     {
           
           AudioInputStream      audioInputStream = null;
                                   
           try
           {
                 audioInputStream = AudioSystem.getAudioInputStream( data );
           }
           catch (Exception e)
           {
                 e.printStackTrace();
           }
           
           create( audioInputStream );
     }
     
     public void createClip( byte[] data ) //does not work
     {
           
           AudioInputStream      audioInputStream = null;      
                                         
           try
           {
                 
                 audioInputStream = AudioSystem.getAudioInputStream( new ByteArrayInputStream( data ) );
           }
           catch (Exception e)
           {
                 e.printStackTrace();
           }
           create( audioInputStream );
     }      
     
     private void create( AudioInputStream audioInputStream )
     {
           if (audioInputStream != null)
           {
                 AudioFormat      format = audioInputStream.getFormat();
                 DataLine.Info      info = new DataLine.Info(Clip.class, format);
                 try
                 {
                       m_clip = (Clip) AudioSystem.getLine(info);
                       m_clip.addLineListener( this );      
                       m_clip.open(audioInputStream);
                       
                 }
                 catch (LineUnavailableException e)
                 {
                       e.printStackTrace();
                 }
                 catch (IOException e)
                 {
                       e.printStackTrace();
                 }            
                 m_clip.loop(100);      //just make it loop
           }
           else
           {
                 System.out.println("bad audio file");
           }
           
     }
Offline aikarele

Senior Newbie





« Reply #1 - Posted 2003-08-30 16:43:42 »

Although it should not be a problem to create an AudioInputStream using byte array, you could create one even easier directly using ZipFile.getInputStream. Unless there is a specific reason why you need to use byte[] instread...


ZipFile zf = new ZipFile("test.zip");
Enumeration entries = zf.entries();

ZipEntry ze = (ZipEntry) entries.nextElement();
while(!ze.getName().equals("music.wav")) {
   ze = (ZipEntry) entries.nextElement();
}

AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(zf.getInputStream(ze));

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