Any Key Pressed

[Mojomonkey]

Looking at the javadoc I don't see a way to see if there is a keypress without explicitly checking a keycode. I'm not using buffered mode. What I would like to do is something like...

Keyboard.isKeyDown(KEY_ANYKEY);

is this possible and I'm just missing something. If it isn't possible any chance it will become possible?

thanks.

[Matzon]

uhm

1   2   3   4

Keyboard.poll();       if(Keyboard.isKeyDown(Keyboard.KEY_A)) {     ... //do stuff }

should do fine?

[Mojomonkey]

uhm yourself.

That only returns true if 'A' is pressed. I want an option that returns true if any key is pressed, false if no keys are pressed.

Games published by our own members! Check 'em out!

[princec]

Just do:

1   2   3   4   5   6   7

boolean keyPressed = false; for (int i = 0; i < 255; i ++) { if (Keyboard.isKeyDown(i)) { keyPressed = true; break; } }

That's all you need to do. Nothing clunky about it at all either. We don't need to do it in LWJGL, because it's beyond our remit.

Cas

[Mojomonkey]

ok, that's what I was doing now, just wanted to see if I could move some code out.  

Thanks.

[psiegel]

You could also switch from polling to buffered keyboard input.

1   2   3   4   5   6   7   8   9   10   11   12   13

Keyboard.create(); Keyboard.enableBuffer(); ... Keyboard.read(); while (Keyboard.next()) {   if (Keyboard.state) {     // A key has been pressed        // Don't break out of while loop, we need to eat    // all the keyboard events to empty the buffer.  } }

[Mojomonkey]

In my current implementation it is better for me to drop some keys over taking the time to check all of them. I originally had it buffered, but a single key press would add too many instances of a keypress. I found that just polling and checking for the key allowed me to drop extraneous key presses without the user noticing.

[Matzon]

uhm yourself.

DOH! - misread your post